704. Binary Search

Easy

Given an array of integers nums which is sorted in ascending order, and an integer target, write a function to search target in nums. If target exists, then return its index. Otherwise, return -1.

You must write an algorithm with O(log n) runtime complexity.

Example 1:

Input: nums = [-1,0,3,5,9,12], target = 9
Output: 4
Explanation: 9 exists in nums and its index is 4

Example 2:

Input: nums = [-1,0,3,5,9,12], target = 2
Output: -1
Explanation: 2 does not exist in nums so return -1

Constraints:

1 <= nums.length <= 10⁴
-10⁴ < nums[i], target < 10⁴
All the integers in nums are unique.
nums is sorted in ascending order.

class Solution {
    public int search(int[] nums, int target) {
        int pivot, left = 0, right = nums.length - 1;
        while (left <= right) {
          pivot = left + (right - left) / 2;
          if (nums[pivot] == target) return pivot;
          if (target < nums[pivot]) right = pivot - 1;
          else left = pivot + 1;
        }
        return -1;
    }
}